Mr. sawyer drove his car from his home to new york at the rate of 45 mph and returned over the same road at the rate of 40 mph. if his time returning exceeded his time going by 30 min, find his time going and his time returning.

time in going is 4 hours, and time in returning is 4.5 hours.

Step-by-step explanation:

Let the distance be d.

Let the time taken in going to New York be 't'.

Since returning time exceeded by 30 min (i.e. 05 hr), so time returning will be t+0.5.

From Home to New York,

d=s*t, so d=45*t

From New York to Home,

d=40 * (t+0.5)

Since distance (d) from home to new york & vice versa is same, we have-

45*t=40 (t+0.5)

9t=8t+4

so, t=4 hours

Hence time in going is 4 hours, and time in returning is 4.5 hours.

stew reads at the fastest rate of 265 words per minute.

step-by-step explanation:

it's a given that felicia reads at 260 word per minute and on connie's graph we can see that she reads 200 words per minute. since stew's table tells us that he read 795 in 3 minutes, we can divide 795 by 3 to find out how many words he reads per minute.

795/3 = 265

stew reads 265 words per minute - he reads at the fastest rate since felecia reads at 260 words per minute and connie reads at 200 words per minute.

stew (265) > felecia (260) > connie (200)