In order to solve the system of linear equations, the coefficients of one of the variables must be the same number but opposite signs. choose a variable to eliminate by multiplication and /or addition. in complete sentences, tell which variable you would choose to eliminate first, and explain why you chose that variable. in detail, explain the steps you took in order to eliminate the first variable and solve for the second variable.
2x+3y=6
5x+2y=4
complete your work in the space provided or upload a file that can display math symbols if your work requires it

Step-by-step explanation:

because both equations do not have matching numbers for the x or y variable, and both equations are positive you are going to have to multiply each equation by a number  so that there will be at least one variable with the same number but with opposite signs.

it does not matter which variable you choose.

lets use y because 2 and 3 are smaller then 2 and 5.

so lets multiply the first equation by 2 in order to get y equal to 6.

2(2x)+2(3y)=(2)6

(do not forget to multiply what the equation is equal to also)

4x+6y=12

now for the second equation we need y to equal negative 6

-3(5x)+-3(2y)=-3(4)

-15x-6y=-12

now lets put the 2 new equations next to each other and see what we can cancel out

4x+6y=12

-15x-6y=-12

-11x=0

x=0

now plug 0 in for x and solve for y (it does not matter which of the 4 equations you choose to solve.

2(0)+3y=6

3y=6

y=2

so your answer is x=0, y=2

the graph on the bottom right