Factor x^3+2x^2-9x-18, given that -2 is a zero.

a. (x+2)(x-√3)(x+√3)=0
b. (x-2)(x-3)(x+3)=0
c. (x-2)(x^2-9)=0
d. (x+2)(x-3)(x+3)=0

x³ + 2x² - 9x - 18 = 0

x²(x+2) - 9(x+2) = 0

(x + 2)(x² - 9) = 0

(x + 2)(x - 3)(x + 3) = 0

the answer is d.

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

yes

step-by-step explanation: