Solve the equation on the interval 0 ≤ θ < 2π.

2 cos ^2 θ - 3 cos θ + 1 = 0

would really appreciate answer for this.

{0, π/3, 5π/3}

Step-by-step explanation:

Let x = cos θ. Then:

2x² - 3x + 1 = 0

x = (3 ± 1)/4

x1 = 1, x2 = 1/2

If cos θ = 1, then θ = 0

If cos θ = 1/2, then θ = π/3 or 5π/3

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.