What is x+3 divided by x-2 and then multiplied by x+2?

(x+3)/(x-2)*(x+2)

(x^2+5x+6)/(x-2)

This is one single fraction. The stuff up top is x^2+5x+6. The stuff down below is x-2

Work Shown:

We multiply out the expressions (x+3) and (x+2) as they are both in the numerator. If you want, you can think of (x+2) as (x+2)/1

Multiplying (x+3) and (x+2) gives us this

(x+3)(x+2) = x(x+2) + 3(x+2) ... see note below

(x+3)(x+2) = x^2+2x + 3x + 6

(x+3)(x+2) = x^2 + 5x + 6

This is the stuff that will be on top in the final answer. The denominator x-2 stays the same.

note: I used the distribution property (a+b)(c+d) = a(c+d)+b(c+d)

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17