X^5-2x^4
divided by
x^2+6x-16

determine what value(s), if any, of the variable must be excluded.

select the number of values that must be excluded.

x  ≠-8          x ≠ -2

Step-by-step explanation:

We cannot divide by zero, so the denominator cannot equal zero

X^2+6x-16≠0

Factor

(x+8) (x-2) ≠0

Using the zero product property

(x+8)  ≠0     (x-2) ≠0

x  ≠-8          x ≠ -2

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: