What is the surface area of the square pyramid represented by the net?

The surface area of the square bottom = L x W = 7 x 7 = 49 cm^2

The area for one of the triangles = 1/2 x base x height = 1/2 x 7 x 9 = 31.5 cm^2

There are 4 triangles, the total area for the triangles = 31.5 x 4 = 126 cm^2

Total area = base  + triangles = 49 + 126 = 175 cm^2

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: