Asum of money was to be shared among three friends. albert, michael and moses in the ratio of 3: 5: 6. if michael received $196 more than albert, find the sum of money shared

The sum of the money shared is $1372

Step-by-step explanation:

The given ratio is

Albert:Michael:Moses=3:5:6

The total ratio is 3+5+6=14

Let the sum of money shared be $.

Then Albert's share

dollars.

Michael's share

dollars.

If Michael received $196 more than Albert, then the difference between their share is the $196.

dollars.

Clear the fraction by multiplying through with 14.

Divide both sides by 2 to get;

3x + 4y -25 =0 represents the amount of change sianna should recieve

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb