Amodel rocket is launched with an initial upward velocity of 65/ms . the rocket's height h (in meters) after t seconds is given by the following. h=65t-5t^2 find all values of t for which the rocket's height is 25 meters. round your answer(s) to the nearest hundredth. (if there is more than one answer, use the "or" button.) ground h

➷

Minus 56 and add to both sides

Divide by 5 to get

Substitute these values into the quadratic equation to give you the answers:

0.40s and 12.60s

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t≈0.40

t≈12.6

Step-by-step explanation:

h=65t-5t^2

Let h = 25

25=65t-5t^2

Subtract 25 from each side

25-25=-25 +65t-5t^2

0 = -5t^2 +65t -25

Using the quadratic formula

where a =- 5 b= 65 and c=-25

-b ± sqrt (b^2 -4ac)

2a

-65 ± sqrt (65^2 -4(-5)(-25))

2(-5)

-65 ± sqrt (4225 -250))

-10

-65 ± sqrt (3975))

-10

t≈0.39672

t≈12.603

Rounding to the nearest hundredth

t≈0.40

t≈12.6

need more information

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!