Kathy and cheryl are walking in a fundraiser. kathy completes the course in 4.8 hours and cheryl completes the course in 8 hours. kathy walks 2 miles per hour faster than cheryl. find kathy's speed and cheryl's speed.

Kathy's speed is equal to

Cheryl's speed is equal to

Step-by-step explanation:

Let

x-----> Kathy's speed

y----> Cheryl's speed

d----> the distance in miles

t----> the time in hours

s-----> the speed in miles per hour

we know that

The speed is equal to the distance divided by the time

so

solve for the distance d

In this problem

----> equation A

Kathy's speed

we have

substitute in the formula of distance

-----> equation B

substitute equation A in equation B

------> equation C

Cheryl's speed

we have

substitute in the formula of distance

-----> equation D

Remember that the distance is the same in both cases

so

equate equation C and equation D and solve for y

Find the value of x

----->

she was supposed to add the hours(38.5) and multiply the amount of money she earned(7.50) resulting in $288.75 .

correct me if i'm wrong and if it is i'm truly sorry.

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: