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Mathematics, 01.10.2019 10:30 xxmimi7xx

Factor completely.

49t^6 - 4k^8

a.) (7t³ + 2k^4)(7t³ - 2k^4)
b.) (7t³ - 2k^4)(7t³ - 2k^4)
³ + 2k^4)(7t³ + 2k^4)

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Answers: 1

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You know the right answer?
Factor completely.

49t^6 - 4k^8

a.) (7t³ + 2k^4)(7t³ - 2k^4)
b.) (7t³...
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