Complete the square x^2 - 6 + = -13 +

x^2 - 6x + __9__ = -13 + __9___

Step-by-step explanation:

x^2 - 6x + = -13 +

To complete the square

we take the coefficient of the x term, divide by 2 and square it

-6 /2 = -3

Then square it

(-3)^2=9

What we add to one side, we add to the other

x^2 - 6x + __9__ = -13 + __9___

x^2 - 6x + 9 = -13 + 9

Step-by-step explanation:

x^2 - 6 + = -13 +

I assume that the second term is -6x, not just -6.

x^2 - 6x + = -13 +

To complete the square, take the x-term coefficient, -6, halve it, -3, and then square it, (-3)^2 = 9. Now add 9 to both sides.

x^2 - 6x + 9 = -13 + 9

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

no

step-by-step explanation: