What is the value of x?

question 2 options:

39

41

31

49

41

Step-by-step explanation:

We can use the Pythagorean theorem to solve for x

a^2 +b^2 = c^2 where a and b are the legs and c is the hypotenuse

9^2 +40^2 = x^2

81 +1600 = c^2

1681 = c^2

Take the square root of each side

sqrt(1681) = sqrt(c^2)

41 = c

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.