How do you find the total surface area of a figure? with a height, width, and length?

See example below.

Step-by-step explanation:

Top prism:

To find the surface area of a prism, find the area of the triangular base and the area of each rectangular side.

Area of the base is A = 1/2 * b*h = 1/2 * 3 * 8 = 12. Since there are 2 bases, the area is 24.

Area of the rectangular side is A = b*h = 2.8*5 = 14. Since there are two, the area is 2*14 = 42.

The surface area of the prism is 24 + 28 = 52.

Bottom prism:

To find the surface area of the bottom prism, find the area of the base and each side of the house.

A = 8*2.8 = 22.4

A = 8*4.8 = 38.4 which occurs twice so it has a total area of 76.8

A = 2.8*4.8 = 13.44 which occurs twice so it has an area of 26.88.

The total volume is 33.6 + 107.52 = 141.12

The total surface area is 52 + 22.4 + 76.8 + 26.88 = 178.08

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

the answers c