Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of the numbers is 5 and the product of the numbers is 6.

enter your answer as a number, like this: 42

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

Step-by-step explanation:

Given :  the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

Since, given the difference of the squares of the numbers is 5 that is

And the product of the numbers is 6 that is

Using identity, we have,

Substitute, we have,

Simplify, we have,

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

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step-by-step explanation:

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