Wayne asked every student in his class how many siblings (brothers and sisters) they had. the survey results are shown in the table below. (wayne included himself in the results.)

what is the probability that a randomly selected student does not have any siblings?

question 4 options:

0/32

1/8

7/8

14/32

The correct answer is 1/8

Step-by-step explanation:

In order to find this, we need to find out how many people have 0 siblings (4 people).

Now we need to find the total number of people surveyed. We can do this by adding all the numbers in the bottom row.

4 + 5 + 14 + 6 + 3 = 32

Now divide the number with 0 siblings by the total.

4/32 = 1/8

50-60=10

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752