Express answer in exact form. show all work for full credit.
a regular hexagon with sides of 3" is inscribed in a circle. find the area of a segment formed by a side of the hexagon and the circle.
(hint: remember corollary 1--the area of an equilateral triangle is 1/4s²√3.)

i am totally lost need show work (75 points)

Area = 23.38 square"

Step-by-step explanation:

It is given that a regular hexagon is having a side = 3"

Since hexagon is inscribed in a circle therefore all the triangles formed by the radii and the sides of hexagon will be equilateral triangles.

In a hexagon number of triangles formed = 6

Area of an equilateral triangle = 1/4s²√3

By putting the value of s = 3"

Area of one triangle = 1/4×3²√3 = (9√3)/4

and we know number of triangles formed inside the hexagon = 6

Therefore area of hexagon = 6×(9√3)/4 = 23.38 square"

Answer is 23.38 square"

i think the person above is correct

Step-by-step explanation:

3x3 = 9 and 2x2 = 4

step-by-step explanation:

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680