10 answer immediately!

1. what does it mean for the ratio of surface area to volume to be small or large? which ratios are better economically?

2. khianna says that she found a shortcut to calculate the surface area to volume ratio.

here are her steps:
1. add the radius and height.
2. multiply the radius and height.
3. divide the result from step 1 by the result in step 2.
4. multiply the result from step 3 by 2.

evaluate this process. does it seem to work? would it work for all 3-d figures? how does this method compare to the method you used?

1. When the ratio of surface area is small, it means that a small covering or container is needed to hold that volume while a big ratio means a large covering or container is needed to hold that same volume. The small ratio is better economically because it saves packaging costs and saves materials.

2.  process doesn't work in which in step 3 she divided step 1 by step 2 then multiplied the result by step 2 in which leaves us with just step 1. Since, step 1 is just a sum, it's not a ratio and therefore the method does not work at all. It wouldn't work for any 3D figures since it doesn't work but it wouldn't work for 3D figures that are not spheres, cones, and cylinders especially as they don't have radii. Her method compared to my method is just a no brainer as me method actually works.

the system of inequalities is

step-by-step explanation:

step 1

find the equation of the dashed line

we have the points

(0,0) and (3,1)

the line passes through the origin, so, is a direct variation

find the slope

the equation of the dashed line is

the solution of the inequality a s the shaded area above the dashed line

therefore

the equation of the inequality a is

step 2

find the equation of the solid line

we have the points

(4,0) and (0,4)

find the slope

the equation of the solid line is

the solution of the inequality b s the shaded area below the solid line

therefore

the equation of the inequality b is

step 3

the system of inequalities is

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step-by-step explanation: