Solve for x in the equation x2-8x+41=0

d) 4 ± 5i

Step-by-step explanation:

Here we have to use the quadratic formula.

x =

In the given equation x^2 - 8x + 41 = 0, a =1, b = -8 and c = 41

Now plug in the given values in the above formula, we get

x =

Simplifying the above, we get

x =

x =

[√-100 = √-1 *√100 = i*10 = 10i] because the value of √-1 = i]

x = (8 ± 10i )/2

Now dividing by 2, we get

x = 4 ± 5i

The answer is d) 4 ± 5i

Hope you will understand the concept.

Thank you.

not me

step-by-step explanation:

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