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consider the recursively defined function below.

f(1)=10
f(n)=2.2 * f(n-1), for n= 2,3,

create the first five terms of the sequence defined by the given function.

Step-by-step explanation:

The given function is defined recursively by;

When n=2,

When n=3,

When n=4,

f(2) = 22  f(3) = 48.4 and f(4) = 106.48

Step-by-step explanation:

Recursively defined function is f(n) = 2.2 [ f(n-1) ] Here, f(1) = 10 then we have to create the first three terms of the sequence defined by the function.

Since f(1) = 10

f(2) = 2.2 [ f (2-1) ] = 2.2 [ f (1) ]

     = 2.2 × 10 = 22

f (3) = 2.2 [ f (3-1)] = 2.2 × [ f (2) ]

      = 2.2 × 22 = 48.4

f(4)  = 2.2 [ f(4-1) ] = 2.2 [ f(3) ]

     = 2.2 × 48.4 = 106.48

Answer is f(2) = 22  f(3) = 48.4 and f(4) = 106.48

d) the triangle is a right triangle 60 squared +144 squared= 156 squared

step-by-step explanation:

156 squared is the hypothenuse

so 156= c