The zeros of a quadratic function are -6 and -2. what is a possible vertex of the function? explain your answer and show your work .

a. (-4, -3)
b. (4, -2)
c. (4, 6)
d. (8, -4)

(-4,-4)

Step-by-step explanation:

If the zeros of a quadratic function are -6 and -2, then it is:

(x+6)(x+2)

Expanding:

(x+6)(x+2)

=x^2+8x+12

To find the vertex, complete the square.

x^2+8x+12

=(x^2+8x+16)-16+12

=(x+4)^2-4

When the quadratic formula is written in the form y = a(x-h)^2+k, the vertex is (h, k).

(h, k)=(-4,-4)