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  sqrt(ac)

±  = b

    3c

Step-by-step explanation:

a= 9b^2 c

Divide each side by 9c

a/9c = 9b^2c / 9c

a/9c= b^2

Take the sqrt of each side

±sqrt(a/9c) = sqt(b^2)

Remember that sqrt (xy) = sqrt(x) sqrt(y)

±sqrt(a/c) * 1/ sqrt(9) = b

±sqrt(a)     1

* = b

sqrt(c)     3

Multiply  by sqrt(c)/ sqrt(c)

±sqrt(a)     sqrt(c)

*   = b

sqrt(c)     3sqrt(c)

±sqrt(ac)

 = b

3c

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."