There are 10 cars in today’s grand prix race in how many different ways can three cars win first second and third places

The number of ways it could be done is:

720

Step-by-step explanation:

It is given that:

There are 10 cars in today’s Grand Prix race.

We have to find the different number of ways these three cars  win first second and third places.

That is we have to choose the three cars and arrange them in ways as according to they obtain there ranks.

Hence, we will use the method of permutation since we have to choose three cars and also arrange them according to their order they finished the race and took first, second and third place.

Hence, the number of ways it could be done is:

Here we have n=10 and r=3.

Hence,

Hence, the number of ways it could be done is:

720

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

111

step-by-step explanation: