In the straightedge and compass construction of the equilateral triangle below, which o the following reasons can you use to prove that abc = bca?

Option 1 is the correct answer.

Step-by-step explanation:

In first circle AC ≅ AB radii of same triangle. Similarly in second circle sides AB ≅ BC radii of second circle.

Since AC ≅ AB and AB ≅ BC

Therefore AC ≅ BC ≅ AB

Since all the sides of the triangle ABC are equal therefore triangle is an equilateral triangle.

And we know in an equilateral triangle all the angles are equal so ∠ABC = ∠BCA.

Option 1 is the answer.

other answer is correct. i had used the radius of the radius somehow. a website: