What is an equation of thebline that is parallel to y=4x-1 and that passes through point (-3,5)

The equation would be y = 4x + 17

Step-by-step explanation:

To find this line, start with the slope. Since it is parallel to the first line and parallel lines have the same slope, we know the slope to be 4. Given this we can use point-slope form and solve for y to get the equation.

y - y1 = m(x - x1)

y - 5 = 4(x + 3)

y - 5 = 4x + 12

y = 4x + 17

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

i believe that the answer is

b. y-1=-2(x-4)

hope this !