What is the equation of the line parallel to 3x-y-7=0 that passes through point (-5, -3)

The equation of the line in slope-intercept form is y =3x+12

Step-by-step explanation:

The first step is to rewrite the equation of the line in the slope-intercept form in order to identify the slope of the line. The re-written equation is;

y = 3x-7.

This implies that the slope of the line is 3. Since the two lines are parallel they they will have equal slope of 3. The slope-intercept form of the equation of this line will be;

y =3x+c.

Since the line passes through (-5, -3), substitute x with -5 and y with -3 to solve for c;

-3 =3(-5)+c.

We find c =12 and the equation of the line becomes;

y =3x+12.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

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