Use the limit theorem and the properties of limits to find the horizontal asymptotes of the graph of the function h(x) = 2x2-6x+1/2+x-x2

Option c is answer

Step-by-step explanation:

A function is given as

Limit is to be found out for x tends to infinity.

We find that numerator and denominator has the same degree.

HEnce a horizontal asymptote exists

COefficients of leading terms are 2 and -1 respectively

Asymtote would be y =2/-1 = -2

Alternate method:

When x tends to infinity, 1/x tends to 0

by dividing both numerator and denominator by square of x.

Now take limit as 1/x tends to 0

we get

limit is y tends to 2/-1 =-2

Hence horizontal asymptote is y =-2

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.

answer: i think it is (1,-2)