Find the solution to the system of equations -3x-9y=18 and 4x+3y=12

(6, - 4)

Step-by-step explanation:

Given the 2 equations

- 3x - 9y = 18 → (1)

4x + 3y = 12 → (2)

Multiplying (2) by 3 and adding the result to (1) eliminates the term in y

12x + 9y = 36 → (3)

Add (1) and (3) term by term

(- 3x + 12x) + (- 9y + 9y) = (18 + 36)

9x = 54 ( divide both sides by 9 )

x = 6

Substitute x = 6 into (1) or (2) and solve for y

(2) : 24 + 3y = 12 ( subtract 24 from both sides )

3y = - 12 ( divide both sides by 3 )

y = - 4

Solution is (6, - 4)

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

x=0

step-by-step explanation: