This graph has rotational symmetry about the points

Answer for figure one is origin (0,0)

Answer for figure two is (2,4) /

Step-by-step explanation:

a) Here we can see that given graph is the equation of cubic function which is

f(-x) = -f(x) that is given function is odd then rotational symmetry point is origin always ,therefore point of rotational symmetry is origin (0,0)

b) The rotational symmetry of  an ellipse is 180 degrees about the center  of  the ellipse .

And here the center of given ellipse is  (2,4) ,therefore its rotational  symmetry is about (2,4) That is if we rotate the given ellipse 180 degrees about (2,4) it will be at its original position.

left: (0,0)

right: (2,4)

Step-by-step explanation:

took quiz on edge2020

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.