Which of the following is true of the data set represented by the box plot?

box plot with point at 16, min at 33, q1 at 40, median at 52, q3 at 55, max at 78, and point at 86

the greatest value in the set is 79.
the data is evenly distributed throughout the middle half.
the data has an iqr of 45.
removing the outliers would not affect the median.

Step-by-step explanation:

The outliers represent those values that lie outside, that is, they are much smaller or much larger than the rest of the values.

So, in this case, outliers refer to the least and greatest value, if we remove them, the median would be the same, because they median is the center of all values, so, if we eliminate the least and the greatest at the same time, the center would remain the same.

The only way to affect the median is by eliminating the least or the greatest value, if we eliminate just one of them, the median would be affected.

Therefore, the right answer is the last choice.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!