Iwill award !
in △abc, ∠b = 90°, bh = ah, and the ratio of m∠a to m∠c is 1: 2. find m∠bha?
a. 100°
b. 90°
c. 120°
d. 60°

C. 120°

Step-by-step explanation:

Let angle A be x, then angle C is 2x

The sum of the angles in ABC is

A + B+ C = 180

x+90 +2x = 180

3x +90 = 180

3x= 90

Divide by 3

x = 90/3

x = 30

Angle A = 30,  Angle C = 2x = 60

AH = BH, so it is an isosceles triangle .  That means A and ABH are equal

A = 30 , ABH = 30

The sum of the angles in ABH must equal 180

A + ABH + BHA = 180

30 + 30 + BHA = 180

60 + BHA = 180

BHA = 180-60

BHA = 120

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

x/3-10=8

x/3=18

x=48