Find the perimeter of a regular heptagon with consecutive vertices at a(? 1,? 2) and b(4, 10)

The perimeter is ≈ 59.808 units

Explanation:

A regular heptagon is a polygon that has 7 equal sides.

To get its perimeter, we need to get the length of only one side and multiply it by 7

1- getting side length:

We are given that there are two consecutive vertices at (1,2) and (4,10)

The length of the side can be calculated using the distance formula as follows:

Length = units

2- getting the perimeter:

Perimeter = 7 * side length

Perimeter = ≈ 59.808 units

Hope this helps :)

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

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step-by-step explanation: