Write an equation in slope intercept form for a line that goes through the point (-9,4) and is perpendicular to line y=-3x-2

y = (1/3)x + 7

Step-by-step explanation:

The slope of a line perpendicular to the given line y = -3x - 2 would have to be the negative reciprocal of the slope of the given line:

or, in other words,

the negative reciprocal of -3.  That would be +1/3.

Starting with the slope-intercept form of the equation of a straight line, we have:

y = mx + b.  

We substitute the coordinates of the given point, (-9,4), and the slope +1/3:

4 = (1/3)(-9) + b.

This simplifies to

4 = -3 + b, from which it can be easily seen that b = 7.

The desired line is y = (1/3)x + 7.

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb