What is the quadratic in vertex form that has an a value of 8 and a vertex of (5, 6)?
answer choices in image,

y= 8(x-5)² + 6

Step-by-step explanation:

Parabolas have two equation forms, namely; the standard and vertex form.

In the vertex form, y = a(x - h)² + k, the variables h and k are the coordinates of the parabola's vertex.

In this case; a=8, h =5, and k=6

Therefore;

The vertex equation will be

y= 8(x-5)² + 6

Choice C is correct.

Step-by-step explanation:

We have to find the equation of quadratic equation in vertex form.

We have given a= 8 and vertex =(5,6)

The general form of vertex form of equation is :

y = a(x-c)²+d

Where (c,d)   is the vertex of equation.

Putting the values on above equation we get,

y = 8 (x-5)² +6

y = 8 (x-5)² +6 is the quadratic equation in vertex form.

So, choice C is  correct.

is there any photos or whatever?

29933333.33

step-by-step explanation: