How much p² – q² + 2pq is less than -2p² -2q² + 7pq +10 ?

  3p² + q² - 5pq - 10 < 0

Step-by-step explanation:

p² - q² + 2pq < -2p² - 2q² + 7pq + 10

since you didn't specify what to solve for, move everything from the right side to the left side of the inequality symbol using inverse operations.

(p² + 2p²) + (- q² + 2q²) + (2pq - 7pq) + (- 10) < 0

    3p²      +        q²        +      -5pq       +   -10  < 0

3p² + q² - 5pq - 10  < 0

step-by-step explanation:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!