Solve the system of equations using substitution. 3x + 2y = 7 y = –3x + 11 (6, –3) (5, –4) (6, –7)

(5, -4)

Step-by-step explanation:

3x + 2y = 7

y = –3x + 11

The second equation is already solved for y, so since y = -3x + 11, we substitute y in the first equation with -3x + 11.

First equation

3x + 2y = 7

3x + 2(-3x + 11) = 7

3x - 6x + 22 = 7

-3x + 22 = 7

-3x = -15

x = 5

Now we use the second original equation and substitute 5 for x. Then we solve for y.

y = -3x + 11

y = -3(5) + 11

y = -15 + 11

y = -4

Solution: (5, -4)