Write the equation in vertex form.
f(x) = x^2 + 10x - 5

y =  (x +5)² - 30 where vertex for the parabola is (-5,-30).

Step-by-step explanation:

We have given a function:

f(x) = x² + 10x - 5

We have to find  the vertex form given form.

Let y = f(x)

y= x² + 10x - 5

The general vertex form :

y = a(x-h)²+h

First, we have to complete the square we have,

y= x² + 10x - 5

y = x² +2(x)(5)-5 +(5)²-(5)²

y = (x +5)²-5-25

y =  (x +5)² - 30

y =  (x +5)² - 30 where vertex for the parabola is (-5,-30).

d) the triangle is a right triangle 60 squared +144 squared= 156 squared

step-by-step explanation:

156 squared is the hypothenuse

so 156= c

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: