f(x)=−2x
2
−5x+1
h(x)=3(x+3)
2
−11

h(f(-1))=h(f(−1))

f(x)=−2x 2−5x+1h(x)=3(x+3) 2−11h(f(-1))=h(f(−1))

2−5h⋅1h

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

1. 34

2. 268

3. x=14.4

step-by-step explanation: