Find the area of parallelogram abcd given m a = 30 and the following measures. ab = 6 ft.; ax = 3√3 a = ? a. 18 ft.² b. 18√3 ft.² c. 36√3 ft.²

Given that a parallelogram ABCD has sides AB= 6 ft and AX = 3√3

Angle A =30

To find the area of the parallelogram

We have area of parallelogram = base x height

Here base can be taken as side AB = 6 ft

Height = perpendicular distance of AB from vertex X

= AX sin A

= 3√3sin30

=1.5√3

Hence area =6(1.5√3)=9√3ft^2

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