Find the x–intercepts of x2 + 8x + 15 = y.

The answer is: x intercepts at -3 and -5.

To find the x-intercepts we just need to find where the function tends to 0,

So,

We can solve this quadratic equation by finding two numbers which its sum give as result 8 and multiplied each other gives as result 15, that numbers would be 3 and 5, knowing that we can rewrite the quadratic equation by the following way:

For the new equation, we just need to find the values of x that make it 0,

When x is -3

When x is -5

So, the intercepts of the given function are: -3 and -5

We can also find the x-intercepts using the quadractic formula:

By substituting we have:

So, the x- intercepts of the given function are: -3 and -5

Have a nice day!

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