Mathematics, 28.11.2019 02:31 Naysa150724

Which ratios are equal to each other? a. 1 : 16 and 2 : 8 b. 2 : 32 and 4 : 8 c. 1 : 64 and 4 : 16 d. 1 : 16 and 4 : 64

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Answer from: rose8969

The answer to the question is d
Which ratios are equal to each other? a. 1 : 16 and 2 : 8 b. 2 : 32 and 4 : 8 c. 1 : 64 and 4

Answer from: kayleerose414

D. 1:16 and 4:64

Step-by-step explanation:

a ratio in the form A:B is the same as $\frac{A}{B}$ , we can simplify the quantities to a fraction that has a numerator of one and thus compare if they are equal or not:

A. 1:16 and 2:8

$\frac{1}{16}$ already has a numerator of one, and $\frac{2}{8}$ if you divide numerator and denominator by two, you get $\frac{1}{4}$ , and since

$\frac{1}{16}$ ≠ $\frac{1}{4}$ , these two ratios are not equal.

B. 2:32 and 4:8

We divide the numerator and denominator of $\frac{2}{32}$ by two to get a numerator of one: $\frac{1}{16}$ and for the second ratio $\frac{4}{8}$ we divide by four: $\frac{1}{2}$ and since

$\frac{1}{16}$ ≠ $\frac{1}{2}$ , these two ratios are not equal.

C. 1:64 and 4:16

$\frac{1}{64}$ already has a numerator of one, and $\frac{4}{16}$ if you divide numerator and denominator by four, you get $\frac{1}{4}$ , and since

$\frac{1}{64}$ ≠ $\frac{1}{4}$ , these two ratios are not equal.

D. 1:16 and 4:64

$\frac{1}{16}$ already has a numerator of one, and $\frac{4}{64}$ if you divide numerator and denominator by four, you get $\frac{1}{16}$ , and since

$\frac{1}{16}$ = $\frac{1}{16}$ , these two ratios are equal.

the answer is D. 1:16 and 4:64

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

Answer from: Quest

answer is 33

step-by-step explanation:

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