When three squares are joined at their vertices to form a right triangle, the combined area of the two smaller squares is the same as the area of the largest square.
which three squares do not support this statement?
a) answer choice f
b) answer choice g
c) answer choice h
d) answer choice j

I believe it's F.

Step-by-step explanation:

Look closely and u might see that F doesn't really create a triangle.

the awnser is h

Step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

ok thats very interesting