What are the zeros of the function?
g (x)=x^3-x^2-12x

select each correct answer.

a. -4
b. -3
c. 0
d. 3
e. 4

B. -3

C. 0

E. 4

Step-by-step explanation:

g (x)=x^3-x^2-12x

Set this equal to zero

0=x^3-x^2-12x

Factor out an x

0=x(x^2-x-12)

Factor inside the parentheses.

What two numbers multiply to -12 and add to -1

-4*3 = -12

-4+3 = -1

0=x(x-4)(x+3)

Using the zero product property

x=0  x-4=0  x+3=0

x=0  x=4   x=-3

idk

step-by-step explanation:

idk

answer: yes, since the line has a steeper rate of change than the exponential the y-values will be greater and they will only intersect one time.