In a group of 25 students, 12 students play basketball, 11 students play football. five students play both sports. a student is chosen randomly from this group. what is the probability that the student plays either basketball or football?

  18/25 = 72%

Step-by-step explanation:

P(B ∪ F) = P(B) + P(F) - P(B ∩ F)

  = 12/25 + 11/25 - 5/25

  = 18/25

The probability a randomly chosen student plays either sport is 18/25 = 72%.

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.