Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.

i need , .

see explanation

Step-by-step explanation:

Given that the first term is - 10 and the common difference between consecutive terms is - 2, then

To obtain the next term from the previous term subtract 2 from it

- 10 - 2 = - 12, - 12 - 2 = - 14, - 14 - 2 = - 16, - 16 - 2 = - 18 and so on

The first 10 terms are

- 10, - 12, - 14, - 16, - 18, - 20, - 22, - 24, - 26, - 28

60%

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.