The diagonal of a square measured 10 cm. find the length of a side of the square to the nearest tenth.

  7.1 cm

Step-by-step explanation:

Let s represent the side length of the square. The Pythagorean theorem tells you the relationship to the diagonal length is ...

  (10 cm)² = s² +s² . . . . the sum of the squares of the legs is the square of the hypotenuse

  100 cm² = 2s² . . . . . . simplify

  50 cm² = s² . . . . . . . . divide by 2

  √(50) cm = s ≈ 7.1 cm . . . . . take the square root

The length of a side of the square to the nearest tenth is 7.1 cm.

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

56

step-by-step explanation: