What is the equation in standard form of the line shown on the graph

Step-by-step explanation:

We take two points (0,-3) and (4,0)

eq. of line thro' two points is y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)=(0+3)/(4-0)=3/4

Reqd. eq . is y-(-3)=3/4(x-0)

or y=3/4(x)-3

For this case we have that the standard equation of a line is given by:

Where:

m: It's the slope

b: It is the cut point with the y axis.

We have the following points of the graph:

Substituting:

We have:

To find the cut point we substitute a point:

Thus, the equation is:

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answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°