What is 8/9 as a percent rounded to nearest tenth percent

8/9 can also be written as 0.888888889 repeating we then need to multiply this by 100 to get 88.8888889%.  To the nearest tenth percent, we would get 88.9%, wouldn't you agree?

8/9 into a percent is easy.
All you have to do is divide the numerator by the denominator, which means to have the 9 go into 8.
So 8÷9=0.88888. . . 
You know how decimals work to make a percent, all you got to do is move the decimal to places to the right. 
0.888. . = 88.88. . . . 
Now to round to the Tenths.
88.88. . .= 88.9%
88.9% is your answer

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12