Solve the system of equations using substitution -3x + 2y = 12 x = 2y - 8

(-2, 3)

Step-by-step explanation:

Given the system of equations:

-3x + 2y = 12

x = 2y - 8

You can 'substitute' the expression '2y - 8' for the value of 'x' in the first equation and solve for 'y':

-3(2y - 8) + 2y = 12

Distribute: -6y + 24 + 2y = 12

Combine like terms: -4y + 24 = 12

Subtract 24 from both sides: -4y + 24 - 24 = 12 - 24 or -4y = -12

Divide both sides by -4: -4y/-4 = -12/-4  or y = 3

Use y = 3 to solve for 'x':

x = 2(3) - 8 or 6 - 8

x = -2

(-2, 3)

its c or d   take a lucky guess my dude

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length