Timed! anyone know the answer to this algebra 2 problem?

C

Step-by-step explanation:

Choice A

Always start with the function on the far left of the combined function. So for Choice  A, you start with

g(a) = sqrt(a)

Now substitute the function on the right of the combined function into whatever you see on the right. In this question, f(a) goes on both sides of the combined function for a.

g(f(a)) = sqrt(f(a))

but f(a) = a^2 - 4

g(f(a)) = sqrt(a^2 - 4) You can't reduce this any further. A is not the answer.

Choice B

g(a) = 2a - 2       Put f(a) in for all a s

g(f(a)) = 2(f(a)) - 2 Now put in 1/2 a - 1 for f(a) on the right.

g(f(a)) = 2(1/2 a - 1) - 2

g(f(a)) = a - 2 - 2

g(f(a)) = a - 4 which is not the right result. B is not your choice.

Choice C

g(a) = sqrt(a - 5) - 2

g(f(a)) = sqrt( f(a) - 5 ) - 2

g(f(a)) = sqrt( 5 + a^2 - 5) - 2

g(f(a)) = sqrt(a^2) - 2

g(f(a)) = |a| - 2 which is the answer you should get.

step-by-step explanation:

the correct answer option is d. la = πrs.

step-by-step explanation:

we know that for a right cone, the lateral surface area is given by:

lateral area of right cone =

here the value under the square root is equal to slant height so replacing this value by in the formula to get:

lateral area of right cone =

therefore, the correct answer option is d.